Đáp án B

HD: Ta có: \({{E}_{\ell k}}=\left[ Z.{{m}_{p}}+\left( A-Z \right).{{m}_{n}}-{{m}_{C}} \right].{{c}^{2}}\)
\(\Rightarrow \)\(6{{m}_{p}}+5{{m}_{n}}-\dfrac{73,743}{931,5}={{m}_{C}}\) (1)
\(\Rightarrow \)\(5{{m}_{p}}+6{{m}_{n}}-\dfrac{76,518}{931,5}={{m}_{B}}\) (2)
Năng lượng tỏa ra của phản ứng: \(\Delta E=\left( {{m}_{C}}-{{m}_{B}}-{{m}_{e}} \right).{{c}^{2}}\)
\(=\left[ 6{{m}_{p}}+5{{m}_{n}}-\dfrac{73,743}{931,5}-\left( 5{{m}_{p}}+6{{m}_{n}}-\dfrac{76,518}{931,5} \right)-{{m}_{e}} \right].{{c}^{2}}\)
\(=\left[ {{m}_{p}}-{{m}_{n}}-{{m}_{e}}-\dfrac{73,743}{931,5}+\dfrac{76,518}{931,5} \right].{{c}^{2}}\)
\(=\left[ 1,0073-1,0087-0,00055-\dfrac{73,743}{931,5}+\dfrac{76,518}{931,5} \right].931,5=0,958575\,MeV.\) Chọn B.